The 3D structure of ramoplanin was studied by NMR spectroscopy in aqueous solution. A total of 320 interproton distances were determined from a NOESY spectrum and were used as restraints in distance geometry calculations. A structural refinement was carried out by molecular dynamics calculations in a solvent box. The structure of ramoplanin is characterized by two antiparallel beta-strands which are formed by the residues 2-7 and 10-14, respectively. The beta-strands are connected by six intramolecular hydrogen bonds and a reverse beta-turn which is formed by Thr(8) and Phe(9) (in positions i+1 and i+2, respectively). Residues 2 and 14 are connected by a loop consisting of Leu(15), Ala(16), Chp(17), and the side chain of Asn(2). Although residues 14-17 show the formation of a beta-turn, only the N-terminal end of the turn is directly connected to one of the beta-strands (Gly(14)), whereas the C-terminal end (Chp(17)) is linked via the side chain of Asn(2). The 3D conformation of ramoplanin is also stabilized by a hydrophobic cluster of the aromatic sidechains of the residues 3, 9, and 17, This hydrophobic collapse leads to a U-shaped topology of the beta-sheet with the beta-turn at one end and the loop at the other end. The structure found for ramoplanin differs considerably from the published structure of ramoplanose which might be due to a smaller number of NOE distance restraints used in the previous study.