Role of duplicate genes in genetic robustness against null mutations

被引:676
作者
Gu, ZL
Steinmetz, LM
Gu, X
Scharfe, C
Davis, RW
Li, WH
机构
[1] Univ Chicago, Dept Ecol & Evolut, Chicago, IL 60637 USA
[2] Stanford Univ, Sch Med, Dept Biochem, Stanford, CA 94305 USA
[3] Stanford Univ, Sch Med, Stanford Genome Technol Ctr, Stanford, CA 94305 USA
[4] Iowa State Univ, Dept Zool, Ames, IA 50011 USA
[5] Iowa State Univ, Dept Genet, Ames, IA 50011 USA
基金
美国国家科学基金会; 美国国家卫生研究院;
关键词
D O I
10.1038/nature01198
中图分类号
O [数理科学和化学]; P [天文学、地球科学]; Q [生物科学]; N [自然科学总论];
学科分类号
07 ; 0710 ; 09 ;
摘要
Deleting a gene in an organism often has little phenotypic effect(1-5), owing to two mechanisms of compensation(4-10). The first is the existence of duplicate genes: that is, the loss of function in one copy can be compensated by the other copy or copies. The second mechanism of compensation stems from alternative metabolic pathways, regulatory networks, and so on. The relative importance of the two mechanisms has not been investigated except for a limited study, which suggested that the role of duplicate genes in compensation is negligible(10). The availability of fitness data for a nearly complete set of single-gene-deletion mutants of the Saccharomyces cerevisiae genome(11) has enabled us to carry out a genome-wide evaluation of the role of duplicate genes in genetic robustness against null mutations. Here we show that there is a significantly higher probability of functional compensation for a duplicate gene than for a singleton, a high correlation between the frequency of compensation and the sequence similarity of two duplicates, and a higher probability of a severe fitness effect when the duplicate copy that is more highly expressed is deleted. We estimate that in S. cerevisiae at least a quarter of those gene deletions that have no phenotype are compensated by duplicate genes.
引用
收藏
页码:63 / 66
页数:5
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