FORMATION OF DINUCLEAR PALLADIUM(I) HYDRIDE [PD2(MU-H)(MU-CO)((S,S)-BDPP)2]CL BY METHANOLYSIS OR HYDROLYSIS OF PD(COME)(CL)((S,S)-BDPP) ((S,S)-BDPP = (2S,4S)-2,4-BIS(DIPHENYLPHOSPHINO)PENTANE)

The methanolysis of acetylpalladium compound Pd(COMe)(Cl){S,S) -BDPP} (1) in the presence or absence of CO results in the formation of a stoichiometric amount of methyl acetate as well as a 1/1 mixture of PdCl2(S,S)-BDPP} (3) and the dinuclear mu-hydrido-mu-carbonyl complex [Pd2(mu-H)(mu-CO){(S,S)-BDPP}2]Cl (4). During this process, at least 1 equiv of methanol is decarbonylated, forming CO which ends up in the products methyl acetate and the mu-hydrido-mu-carbonyl compound 4.