Explicit space-time codes achieving the diversity-multiplexing gain tradeoff

被引:189
作者
Elia, Petros [1 ]
Kumar, K. Raj
Pawar, Sameer A.
Kumar, P. Vijay
Lu, Hsiao-Feng
机构
[1] Univ So Calif, Dept Elect Engn Syst, Los Angeles, CA 90089 USA
[2] Indian Inst Sci, Dept Elect Commun Engn, Bangalore 560012, Karnataka, India
[3] Natl Chung Cheng Univ, Dept Commun Engn, Chiayi 621, Taiwan
关键词
cyclic division algebra; diversity-multiplexing gain tradeoff; explicit construction; space-time codes;
D O I
10.1109/TIT.2006.880037
中图分类号
TP [自动化技术、计算机技术];
学科分类号
0812 ;
摘要
A recent result of Zheng and Tse states that over a quasi-static channel, there exists a fundamental tradeoff, referred to as the diversity-multiplexing gain (D-MG) tradeoff, between the spatial multiplexing gain and the diversity gain that can be simultaneously achieved by a space-time (ST) code. This tradeoff is precisely known in the case of independent and identically distributed (i.i.d.) Rayleigh fading, for T >= n(t) + n(r) - 1 where T is the number of time slots over which coding takes place and n(t), n(r) are the number of transmit and receive antennas, respectively. For T < n(t) + n(r) - 1, only upper and lower bounds on the D-MG tradeoff are available. In this paper, we present a complete solution to the problem of explicitly constructing D-MG optimal ST codes, i.e., codes that achieve the D-MG tradeoff for any number of receive antennas. We do this by showing that for the square minimum-delay case when T = n(t) - n, cyclic-division-algebra (CDA)-based ST codes having the nonvanishing determinant property are D-MG optimal. While constructions of such codes were previously known for restricted values of n, we provide here a construction for such codes that is valid for all n. For the rectangular, T > n(t) case, we present two general techniques for building D-MG-optimal rectangular ST codes from their square counterparts. A byproduct of our results establishes that the D-MG tradeoff for all T >= n(t) is the same as that previously known to hold for T >= n(t) + n(r) - 1.
引用
收藏
页码:3869 / 3884
页数:16
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