Synthesis and reactions of molybdenum triamidoamine complexes containing hexaisopropylterphenyl substituents

被引:152
作者
Yandulov, DV
Schrock, RR [1 ]
Rheingold, AL
Ceccarelli, C
Davis, WM
机构
[1] MIT, Dept Chem, Cambridge, MA 02139 USA
[2] Univ Delaware, Dept Chem & Biochem, Newark, DE 19716 USA
关键词
D O I
10.1021/ic020505l
中图分类号
O61 [无机化学];
学科分类号
070301 ; 081704 ;
摘要
We have synthesized a triamidoamine ligand ([(RNCH2CH2)(3)N](3-)) in which R is 3,5-(2,4,6-i-Pr3C6H2)(2)C6H3 (hexaisopropylterphenyl or HIPT). The reaction between MOCl4(THF)(2) and H-3[HIPTN3N] in THF followed by 3.1 equiv of LiN(SiMe3)(2) led to formation of orange [HIPTN3N]MoCl. Reduction of MoCl (Mo = [HIPTN3N]Mo) with magnesium in THF under dinitrogen led to formation of salts that contain the {Mo(N-2)}(-) ion. The {Mo(N-2)}(-) ion can be oxidized by zinc chloride to give Mo(N-2) Or protonated to give MoN=NH. The latter was found to decompose to yield MoH. Other relevant compounds that have been prepared include {Mo=N-NH2}(+) (by protonation of MoN=NH), Mo equivalent to N, {Mo=NH}(+) (by protonation of Moequivalent toN), and {Mo(NH3)}(+) (by treating MoCl with ammonia). (The anion is usually {B(3,5-(CF3)(2)C6H3)(4)}(-) = {BAr'(4)}(-).) X-ray studies were carried out on {Mg(DME)(3)}(0.5)-[Mo(N-2)], MoN=NMgBr(THF)(3), Mo(N-2) Moequivalent toN, and {Mo(NH3)}{BAr'(4)}. These studies suggest that the HIPT substituent on the triamidoamine ligand creates a cavity that stabilizes a variety of complexes that might be encountered in a hypothetical Chatt-like dinitrogen reduction scheme, perhaps largely by protecting against bimolecular decomposition reactions.
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页码:796 / 813
页数:18
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