KINETICS OF ELECTRON ENTRY, EXIT, AND INTERFLAVIN ELECTRON-TRANSFER DURING CATALYSIS BY SARCOSINE OXIDASE

Sarcosine oxidase contains 1 mol of covalently bound plus 1 mol of noncovalently bound FAD per active site. The first phase of the anaerobic reduction of the enzyme with sarcosine converts oxidized enzyme to an equilibrium mixture of two-electron-reduced forms (EH2) and occurs at a rate (2700 min-1, pH 8.0) similar to that determined for the maximum rate of aerobic turnover in steady-state kinetic studies (2600 min-1). The second phase of the anaerobic half-reaction converts EH2 to the four-electron-reduced enzyme (EH4) and occurs at a rate (k = 350 min-1) which is 7-fold slower than aerobic turnover. Reaction of EH2 with oxygen is 1.7-fold faster (k = 4480 min-1) than aerobic turnover and 13-fold faster than the anaerobic conversion of EH2 to EH4. The results suggest that the enzyme cycles between fully oxidized and two-electron-reduced forms during turnover with sarcosine. The long wavelength absorbance observed for EH2 is attributable to a flavin biradical (FADH. FAD.-) which is generated in about 50% yield at pH 8.0 and in nearly quantitative yield at pH 7.0. The rate of biradical formation is determined by the rate of electron transfer from sarcosine to the noncovalent flavin since electron equilibration between the two flavins (k = 750 s-1 or 45 000 min-1, pH 8.0) is nearly 20-fold faster, as determined in pH-jump experiments. Only two of the three possible isoelectronic forms of EH2 are likely to transfer electrons to oxygen since the reaction is known to occur at the covalent flavin. However, equilibration among EH2 forms is probably maintained during reoxidation, consistent with the observed monophasic kinetics, since interflavin electron transfer is 10-fold faster than electron transfer to oxygen.